3w^2-30w+100=25

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Solution for 3w^2-30w+100=25 equation: 



3w^2-30w+100=25

We move all terms to the left:

3w^2-30w+100-(25)=0

We add all the numbers together, and all the variables

3w^2-30w+75=0

a = 3; b = -30; c = +75;
Δ = b2-4ac
Δ = -302-4·3·75
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{30}{6}=5$

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